Solution 1

``````def get_largest_numbers(d1, d2, d3):
result = {
"d1": None,
"d2": None,
"d3": None
}

for key, value in d1.items():
if type(value) is int and (result["d1"] is None or result["d1"] < value):
result["d1"] = value

for key, value in d2.items():
if type(value) is int and (result["d2"] is None or result["d2"] < value):
result["d2"] = value

for key, value in d3.items():
if type(value) is int and (result["d3"] is None or result["d3"] < value):
result["d3"] = value
return result``````

# Saving the Largest Value

Write a function `get_largest_numbers` that receives 3 dictionaries as parameters: `d1`, `d2`, and `d3`. Get the highest integer value for each dictionary, and return a new dictionary showing the results of each. If there is a non-integer as a value, ignore it. If none of the values are integers, set that result value to None. Your keys in your result dictionary will be the name of each dictionary parameter (hardcoded to "d1", "d2", and "d3").

Example:

Add all the values with the key 'a' together, and you get the sum 22.

``````d1 = {
'a': 30,
'b': 10,
'c': 5
}

d2 = {
'a': 7,
'b': 'hi',
'c': 90
}

d3 = {
'a': 'aloha',
'b': 'howdy',
'c': 'hello'
}

result = {
'd1': 30,
'd2': 90,
'd3': None
}

get_largest_numbers(d1, d2, d3) == result
``````

### Test Cases

test largest values -

``````def test_largest_values():
d1 = {
'a': 30,
'b': 10,
'c': 5
}

d2 = {
'a': 7,
'b': 'hi',
'c': 90
}

d3 = {
'a': 'aloha',
'b': 'howdy',
'c': 'hello'
}

result = {
'd1': 30,
'd2': 90,
'd3': None
}

assert get_largest_numbers(d1, d2, d3) == result``````
def get_largest_numbers(d1, d2, d3): pass